我们在工作当中经常会遇到填充时间轴的问题,我整理了一份通用“按固定时间间隔补齐时间轴”的sql做法合集,覆盖常见数据库(postgresql、mysql、sql server、sqlite、bigquery、snowflake)。你可以选用与你环境匹配的版本。思路都一样:
- 先生成一条连续的时间序列(按分钟/小时/天等间隔);
- 用这条时间序列和你的数据left join,对缺失点补 0 或空值;
- 再做需要的聚合(如每5分钟求和/计数/均值)。
1) postgresql / amazon redshift(推荐,最简洁)
postgresql 原生有 generate_series,写法非常优雅。
示例:每5分钟补齐一次,统计每5分钟事件数
with ts as (
select generate_series(
timestamp '2025-10-01 00:00:00',
timestamp '2025-10-02 00:00:00',
interval '5 minute'
) as bucket
),
events as (
-- 你的原始数据表,假设字段:event_time (timestamp)
select date_trunc('minute', event_time) as minute_ts
from public.event_log
where event_time >= '2025-10-01 00:00:00'
and event_time < '2025-10-02 00:00:00'
)
select
ts.bucket,
coalesce(cnt.c, 0) as event_count
from ts
left join (
select date_trunc('minute', minute_ts) - (extract(minute from minute_ts)::int % 5) * interval '1 minute'
as bucket_5m,
count(*) as c
from events
group by 1
) cnt
on ts.bucket = cnt.bucket_5m
order by ts.bucket;
如果你的数据已经是整分,就可以把上面的“对5分钟分箱”的表达式简化成
date_trunc('minute', event_time)再对interval '5 minute'进行对齐。
每天/每小时序列只需把 interval '5 minute' 换成 interval '1 hour' 或 interval '1 day',同时聚合逻辑改为 date_trunc('hour'/'day', ...)。
2) mysql 8.0+(使用递归cte)
mysql 没有内置的 generate_series,我们用递归cte造序列。
示例:每15分钟补齐一次
with recursive ts as (
select timestamp('2025-10-01 00:00:00') as bucket
union all
select bucket + interval 15 minute
from ts
where bucket < '2025-10-02 00:00:00'
),
events as (
select event_time
from event_log
where event_time >= '2025-10-01 00:00:00'
and event_time < '2025-10-02 00:00:00'
),
agg as (
select
-- 把 event_time 对齐到 15分钟的时间桶
from_unixtime(floor(unix_timestamp(event_time) / (15*60)) * (15*60)) as bucket_15m,
count(*) as c
from events
group by 1
)
select
ts.bucket,
coalesce(agg.c, 0) as event_count
from ts
left join agg
on ts.bucket = agg.bucket_15m
order by ts.bucket
option max_recursion_depth = 100000; -- 如有需要可调整
性能提示:长时间跨度建议用“辅助数字表/日历表/时间维表”替代递归;或者先生成按天的序列再在应用层扩展。
3) sql server(两种做法:递归cte 或 tally/numbers 表)
3.1 递归cte
with ts as (
select cast('2025-10-01t00:00:00' as datetime2) as bucket
union all
select dateadd(minute, 10, bucket)
from ts
where bucket < cast('2025-10-02t00:00:00' as datetime2)
),
agg as (
select dateadd(minute,
datediff(minute, 0, event_time) / 10 * 10, 0) as bucket_10m,
count(*) as c
from dbo.eventlog
where event_time >= '2025-10-01t00:00:00'
and event_time < '2025-10-02t00:00:00'
group by dateadd(minute, datediff(minute, 0, event_time) / 10 * 10, 0)
)
select ts.bucket,
isnull(agg.c, 0) as event_count
from ts
left join agg
on ts.bucket = agg.bucket_10m
order by ts.bucket
option (maxrecursion 0);
3.2 numbers/tally 表(更高效,推荐生产)
先准备一个连续整数表(可持久化)。随后:
declare @start datetime2 = '2025-10-01t00:00:00'; declare @end datetime2 = '2025-10-02t00:00:00'; with ts as ( select dateadd(minute, n*5, @start) as bucket from dbo.numbers where dateadd(minute, n*5, @start) <= @end ) -- 其余与上面 left join 聚合同理
4) sqlite(递归cte)
with recursive ts(bucket) as (
select datetime('2025-10-01 00:00:00')
union all
select datetime(bucket, '+5 minutes')
from ts
where bucket < '2025-10-02 00:00:00'
),
agg as (
select
datetime(strftime('%s', event_time) / (5*60) * (5*60), 'unixepoch') as bucket_5m,
count(*) as c
from event_log
where event_time >= '2025-10-01 00:00:00'
and event_time < '2025-10-02 00:00:00'
group by 1
)
select ts.bucket, ifnull(agg.c, 0) as event_count
from ts
left join agg on ts.bucket = agg.bucket_5m
order by ts.bucket;
5) bigquery(原生数组函数,非常方便)
with ts as (
select
ts as bucket
from unnest(
generate_timestamp_array(
timestamp('2025-10-01 00:00:00+00'),
timestamp('2025-10-02 00:00:00+00'),
interval 15 minute
)
) as ts
),
agg as (
select
timestamp_trunc(event_time, minute) -
interval mod(extract(minute from event_time), 15) minute as bucket_15m,
count(*) as c
from `project.dataset.event_log`
where event_time >= timestamp('2025-10-01 00:00:00+00')
and event_time < timestamp('2025-10-02 00:00:00+00')
group by 1
)
select ts.bucket, ifnull(agg.c, 0) as event_count
from ts
left join agg
on ts.bucket = agg.bucket_15m
order by ts.bucket;6) snowflake(使用 generator)
with params as (
select
to_timestamp('2025-10-01 00:00:00') as start_ts,
to_timestamp('2025-10-02 00:00:00') as end_ts,
5 as step_min
),
ts as (
select
dateadd(minute, seq4()*step_min, start_ts) as bucket
from params,
table(generator(rowcount => 100000000)) -- 上限要能覆盖区间长度
qualify bucket <= (select end_ts from params)
),
agg as (
select
date_trunc('minute', event_time) -
(date_part(minute, event_time) % 5) * interval '1 minute' as bucket_5m,
count(*) as c
from event_log
where event_time >= (select start_ts from params)
and event_time < (select end_ts from params)
group by 1
)
select ts.bucket, coalesce(agg.c, 0) as event_count
from ts
left join agg on ts.bucket = agg.bucket_5m
order by ts.bucket;
rowcount要覆盖足够的时间点:大致 = (总分钟数 / step_min) + 1。
通用“参数化模版”
把这段思想搬到任何库都成立:
- 定义参数:
start_ts、end_ts、step(分钟/小时/天)。 - 生成连续时间(递归cte、内置序列函数、numbers表、数组生成等)。
- 对齐/分箱:把事实表时间戳落到
step对齐的“时间桶”。 - left join + coalesce:保证缺失点返回 0。
- order by 时间桶。
常见坑 & 优化建议
- 对齐方式:例如 5 分钟分箱要确保所有时间都落在
00,05,10,...,55上。不同数据库对齐写法不同,上面示例已给出。 - 闭区间/开区间:通常建议
[start, end),避免终点重复。 - 时区:原始数据如果是 utc,聚合前先统一到目标时区或全部用 utc,然后在展示层转时区。
- 性能:长时间跨度用日历表/numbers 表最稳。给时间列和分箱列加索引/分区;尽量先裁剪时间范围再聚合。
- 重复数据:分箱前先去重或定义清楚计数口径。
- 窗口边界:如果做移动平均/滑动窗口,先补齐再用窗口函数。
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