一、find查询
事前准备:插入如下数据
db.students.insert([ { _id:1, name:"zhao", age:25, country:"usa", books:["js","c++","extjs","mongodb"]}, { _id:2, name:"qian",age:22, country:"usa", books:["php","java","extjs","c++"]}, { _id:3,name:"sun",age:26, country:"usa", books:["js","java","c#","mongodb"]}, { _id:4, name:"li",age:27,country:"china",books:["js","java","extjs","mongodb"]}, { _id:5,name:"zhou", age:30,country:"china",books:["js","c#","php","mongodb"]}, { _id:6, name:"wu", age:27, country:"japan", books:["js","java","c++","mongodb"]}, { _id:7, name:"zheng", age:27, country:"uk", books:["js","java","extjs","php"]}, { _id:8, name:"wang", age:26, country:"korea",books:["js","c#","extjs","mongodb"]} ])
1.指定返回的键
db.[文档名].find ({条件},{键指定})
查询出所有数据的指定键(name ,age ,country)
db.students.find({},{name:1,age:1,country:1,_id:0})
- ※条件不写就是查询全部
- ※需要查询的就在键后指定为1,不用就指定为0(感觉只要想查的键后面有值不见得非得是1)
- ※如果不指定显示=式_id:0,那查询过程都是带有_id的
2.查询条件
比较操作符 | 意义 | 举例 |
---|---|---|
$lt | < | 查询出id小于5的学生 > db.students.find({_id:{$lt:5}},{}) |
$lte | <= | 查询出年龄小于等于25岁之间的学生 > db.students.find({age:{$lte:25}},{}) |
$ne | != | 查询出国家不是中国的学生 > db.students.find({country:{$ne:"china"}},{}) |
$gt | > | 查询所有年纪大于27岁的,中国学生名字 > db.students.find({age:{$gt:27}},{name:1,country:1,age:1}) { "_id" : 5, "name" : "zhou", "age" : 30, "country" : "china" } |
$gte | >= | 同上 |
3.包含或不包含
较操作符 | 意义 | 举例 |
---|---|---|
$in | 包含 | 查询国家是中国和美国的学生 > db.students.find({country:{$in:["china","usa"]}},{}) |
$nin | 不包含 | 查询年龄不是27岁的学生 > db.students.find({age:{$nin:[27]}},{}) |
4.or查询
较操作符 | 意义 | 举例 |
---|---|---|
$or | 包含 | 查询年龄小于27岁,或者国家是美国的学生 >db.students.find({$or:[{age:{$lt:27}},{country:"usa"}]},{}) 查询年龄大于等于30岁,或者国家是不是美国的学生 >db.students.find({$or:[{age:{$gte:30}},{country:{$nin:["china"]}}]},{}) |
5.null
为所有美国学生添加性别属性为男性(m)
> db.students.update({country:"usa"},{$set:{sex:"m"}},false,true)
查询所有sex属性为null的学生
> db.students.find({sex:{$in:[null]}},{name:1,country:1})
6.正则查询
查询出名字中存在”zh”的学生的信息
> db.students.find({name:/zh/},{}) { "_id" : 1, "name" : "zhao", "age" : 25, "country" : "usa", "books" : [ "js", "c++", "extjs", "mongodb" ], "sex" : "m" } { "_id" : 5, "name" : "zhou", "age" : 30, "country" : "china", "books" : [ "js", "c#", "php", "mongodb" ] } { "_id" : 7, "name" : "zheng", "age" : 27, "country" : "uk", "books" : [ "js", "java", "extjs", "php" ] }
7.$not的使用
※$not和$nin的区别是$not可以用在任何地方儿$nin是用到集合上的
查找出名字中不存在“zh”的学生信息
> db.students.find({name:{$not:/zh/}},{}) { "_id" : 2, "name" : "qian", "age" : 22, "country" : "usa", "books" : [ "php","java", "extjs", "c++" ], "sex" : "m" } { "_id" : 3, "name" : "sun", "age" : 26, "country" : "usa", "books" : [ "js", "java", "c#", "mongodb" ], "sex" : "m" } { "_id" : 4, "name" : "li", "age" : 27, "country" : "china", "books" : [ "js", "java", "extjs", "mongodb" ] } { "_id" : 6, "name" : "wu", "age" : 27, "country" : "japan", "books" : [ "js", "java", "c++", "mongodb" ] } { "_id" : 8, "name" : "wang", "age" : 26, "country" : "korea", "books" : [ "js","c#", "extjs", "mongodb" ] }
8.数组查询$all和index应用
查询所有拥有js和php书籍的同学
> db.students.find({books:{$all:["js","php"]}},{}) { "_id" : 5, "name" : "zhou", "age" : 30, "country" : "china", "books" : [ "js", "c#", "php", "mongodb" ] } { "_id" : 7, "name" : "zheng", "age" : 27, "country" : "uk", "books" : [ "js", "java", "extjs", "php" ] }
查询第三本书是c#的同学
> db.students.find({"books.2":"c#"},{}) { "_id" : 3, "name" : "sun", "age" : 26, "country" : "usa", "books" : [ "js", "java", "c#", "mongodb" ], "sex" : "m" }
上面那个使用index来查询的例子中,"books.2"一定要用""包含起来
9.查询指定长度数组$size
它不能与比较查询符一起使用(这是弊端)
插入一条book数组有两本数的同学
> db.students.insert({_id:9,name:"xu",age:26,country:"japan",books:["c#","php"]}) writeresult({ "ninserted" : 1 })
查询只有两本书的同学
> db.students.find({books:{$size:2}},{}) { "_id" : 9, "name" : "xu", "age" : 26, "country" : "japan", "books" : [ "c#", "php" ] }
查询名字是“li”的喜欢的书的数量
> var person = db.students.find({name:"li"}) > while(person.hasnext()){ obj = person.next(); print(obj.books.length) }
10.$slice操作符返回文档中指定数组的内部值
查询名字为“wang”书架中第1~3本书
> db.students.find({name:"wang"},{books:{$slice:[0,3]}}) { "_id" : 8, "name" : "wang", "age" : 26, "country" : "korea", "books" : [ "js", "c#", "extjs" ] }
查询出最后一本书
> db.students.find({name:"wang"},{books:{$slice:-1}}) { "_id" : 8, "name" : "wang", "age" : 26, "country" : "korea", "books" : [ "mongodb" ] }
11.文档查询
添加一个对象数组到“li”同学,记录“li”同学的成绩
> var li = [{ ... subject :"math", ... score: 90 ... },{ ... subject :"english", ... score:85 ... },{ ... subject :"history", ... score:95 ... }] > db.students.update({name:"li"},{$set:{school:li}}) writeresult({ "nmatched" : 1, "nupserted" : 0, "nmodified" : 1 }) > db.students.find({name:"li"},{}) { "_id" : 4, "name" : "li", "age" : 27, "country" : "china", "books" : [ "js", "java", "extjs", "mongodb" ], "school" : [{ "subject" : "math", "score" : 90 },{ "subject" : "english", "score" : 85 }, { "subject" : "history", "score" : 95 }] } >
查询参加了数学考试,并且分数为90的同学
①.绝对匹配可以
> db.students.find({school:{subject:"math",score:90}},{_id:0,name:1}) { "name" : "li" }
但是问题存在如下:
条件顺序变化时候,
> db.students.find({school:{score:90,subject:"math"}},{_id:0,name:1}) > --查不到东西--
条件数目不一致的时候,也同样查不到
②.为了解决顺序的问题我可以用对象“.”
> db.students.find({"school.subject":"math","school.score":90},{name:1}) { "_id" : 4, "name" : "li" }
这种方式支持顺序的变化,但是也同样存在问题,那就是匹配的问题,条件不是作为一对条件来进行匹配的
例如:
> db.students.find({"school.subject":"math","school.score":85},{name:1}) { "_id" : 4, "name" : "li" }
这里的85分是英语成绩
③.正确做法单条条件组查询$elemmatch
> db.students.find({school:{$elemmatch:{subject:"math",score:90}}},{name:1}) { "_id" : 4, "name" : "li" } > db.students.find({school:{$elemmatch:{score:90,subject:"math"}}},{name:1}) { "_id" : 4, "name" : "li" } > db.students.find({school:{$elemmatch:{subject:"math"}}},{name:1}) { "_id" : 4, "name" : "li" } >
二、分页与排序
1.limit返回指定的数据条数
查询出student文档中前5条数据
> db.students.find().limit(5)
2.skip返回指定数据的跨度
查询出persons文档中3~8条的数据
> db.students.find().limit(5).skip(2)
3.sort返回按照年龄排序的数据[1,-1]
查询所有数据,按照年龄排序
正序
> db.students.find({},{_id:0,age:1,name:1}).sort({age:1}) { "name" : "qian", "age" : 22 } { "name" : "zhao", "age" : 25 } { "name" : "sun", "age" : 26 } { "name" : "wang", "age" : 26 } { "name" : "xu", "age" : 26 } { "name" : "wu", "age" : 27 } { "name" : "zheng", "age" : 27 } { "name" : "li", "age" : 27 } { "name" : "zhou", "age" : 30 }
倒序
> db.students.find({},{_id:0,age:1,name:1}).sort({age:-1}) { "name" : "zhou", "age" : 30 } { "name" : "wu", "age" : 27 } { "name" : "zheng", "age" : 27 } { "name" : "li", "age" : 27 } { "name" : "sun", "age" : 26 } { "name" : "wang", "age" : 26 } { "name" : "xu", "age" : 26 } { "name" : "zhao", "age" : 25 } { "name" : "qian", "age" : 22 } >
skip性能不好,可以采用插入时间的做法来弥补,具体方法如下:
- 1.在每一个记录后面都加入一个插入时间的键值对
- 2.每次取数据的时候都把取出的最后一个数据的时间保存下来,再传给下一次查询
- 3.使用db.persons.find({date:{$gt:日期数值}}).limit(取出的数据数目)比较查询取出要分页的数据
三、游标和其他知识
1.利用游标来查询数据
var persons = db.persons.find(); while(persons.hasnext()){ obj = persons.next(); print(obj.name) }
2.游标几个销毁条件
客户端发来信息叫他销毁
游标迭代完毕
默认游标超过10分钟没用也会别清除
3.查询快照
快照后就会针对不变的集合进行游标运动了,看看使用方法.
db.persons.find({$query:{name:”jim”},$snapshot:true})
为什么用快照,以为mongodb在进行更新的时候,例如添加一些键值对,那么mongodb的处理不会在原来的索引位置上进行更新操作,而是会把
更新之后的数据,放在末尾,那么就导致了前后两次进行查询时候相同索引对应不同数据的情况
补充:
高级查询选项
- $where
- $query
- $orderby
- $maxsan:integer 最多扫描的文档数
- $min:doc 查询开始
- $max:doc 查询结束
- $hint:doc 使用哪个索引
- $explain:boolean 统计
- $snapshot:boolean 一致快照
到此这篇关于mongodb实现查询操作的文章就介绍到这了。希望对大家的学习有所帮助,也希望大家多多支持代码网。
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