三种常见的排名
row_number、dense_rank、rank在mysql 5.7中的实现
准备数据
表结构说明
成绩表 sc(sid,cid,score)
- sid 学⽣编号
- cid 课程编号
- score 分数
创建sc表
create table sc(
sid varchar(10),
cid varchar(10),
score decimal(18,1)
);
插入数据
-- 成绩表 sc
insert into sc values('01' , '01' , 80);
insert into sc values('01' , '02' , 90);
insert into sc values('01' , '03' , 99);
insert into sc values('02' , '01' , 70);
insert into sc values('02' , '02' , 60);
insert into sc values('02' , '03' , 80);
insert into sc values('03' , '01' , 80);
insert into sc values('03' , '02' , 80);
insert into sc values('03' , '03' , 80);
insert into sc values('04' , '01' , 50);
insert into sc values('04' , '02' , 30);
insert into sc values('04' , '03' , 20);
insert into sc values('05' , '01' , 76);
insert into sc values('05' , '02' , 87);
insert into sc values('06' , '01' , 31);
insert into sc values('06' , '03' , 34);
insert into sc values('07' , '02' , 89);
insert into sc values('07' , '03' , 98);
对sc中的学生score进行整体排名
row_number
1 2 3 4 5 6 7 没有重复排名,依次递增
set @i := 0;
set @p := 0;
set @q := 0;
select t1.sid
,t1.cid
,t1.score
,@p := t1.score
,if(@p=@q,@i,@i := @i+1) as dense_rank
,@q :=@p
from (
select sid
,cid
,score
from sc
order by score desc
) t1;
dense_rank
1 2 3 3 3 4 5 6 7 有重复时并列排名,最终排名也是连续的
set @i := 0;
set @p := 0;
set @q := 0;
select t1.sid
,t1.cid
,t1.score
,@p := t1.score
,if(@p=@q,@i,@i := @i+1) as dense_rank
,@q :=@p
from (
select sid
,cid
,score
from sc
order by score desc
) t1;
rank
1 2 3 3 3 6 7 8 有重复时并列排名,最终排名不连续
set @i := 0;
set @j := 0;
set @p := 0;
set @q := 0;
select t1.sid
,t1.cid
,t1.score
,@j := @j + 1
,@p := t1.score
,if(@p=@q,@i,@i := @j) as rank
,@q :=@p
from (
select sid
,cid
,score
from sc
order by score desc
) t1;
进行分组排名
row_number
查询每⻔课程成绩最好的前三名 1 2 3 4 5 6 7 没有重复排名,依次递增
set @i := 0;
set @p := 0;
set @q := 0;
select tt1.sid
,tt2.sname
,tt1.cid
,tt1.score
,tt1.rn
from (
select t1.sid
,t1.cid
,t1.score
,@p := t1.cid
,if(@p=@q,@i := @i + 1,@i :=1) as rn
,@q := @p
from (
select sid
,cid
,score
from sc
order by cid,score desc
) t1
) tt1 join student tt2 on tt1.rn<=3 and tt1.sid = tt2.sid
order by tt1.cid,tt1.rn;
dense_rank
查询每⻔课程成绩最好的前三名 1 2 3 3 3 4 5 6 7 有重复时并列排名,最终排名也是连续的
set @i := 0;
set @p := 0;
set @q := 0;
set @j := 0;
set @k := 0;
select tt1.sid
,tt2.sname
,tt1.cid
,tt1.score
,tt1.rn
from (
select t1.sid
,t1.cid
,t1.score
,@p := t1.cid
,@j := t1.score
,if(@p=@q,if(@j=@k,@i,@i := @i + 1),@i :=1) as rn
,@q := @p
,@k := @j
from (
select sid
,cid
,score
from sc
order by cid,score desc
) t1
) tt1 join student tt2 on tt1.rn<=3 and tt1.sid = tt2.sid
order by tt1.cid,tt1.rn;
rank
查询每⻔课程成绩最好的前三名 1 2 3 3 3 6 7 8 有重复时并列排名,最终排名不连续
set @i := 0;
set @p := 0;
set @q := 0;
set @j := 0;
set @k := 0;
set @m := 1;
select tt1.sid
,tt2.sname
,tt1.cid
,tt1.score
,tt1.rn
from (
select t1.sid
,t1.cid
,t1.score
,@p := t1.cid
,@j := t1.score
,if(@p=@q,@m := @m + 1,@m := 1)
,if(@p=@q,if(@j=@k,@i,@i := @m),@i :=1) as rn
,@q := @p
,@k := @j
from (
select sid
,cid
,score
from sc
order by cid,score desc
) t1
) tt1 join student tt2 on tt1.rn<=3 and tt1.sid = tt2.sid
order by tt1.cid,tt1.rn;
总结
以上为个人经验,希望能给大家一个参考,也希望大家多多支持代码网。
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