我要评论python嵌套的列表储存
简单列表循环清楚了，但是嵌套的列表储存会有点蒙圈，记录下
方式一
调用方法时输出print，方法是直接return输出信息
def get_grade(student_score, name):
for student in student_score:
if student[1] == name:
try:
grade = student[2]
return grade
except indexerror:
return '找不到该同学的成绩'
return "找不到该同学的信息"
student_score = [[1, "lily", 95], [2, "bob", 83], [3, "tom"], [4, "lis", 89]]
a=get_grade(student_score, "tom")
print(a)
b=get_grade(student_score, "234")
print(b)
c=get_grade(student_score, "lily")
print(c)
方式二
方法中写了输出，再return
def get_grade(student_score, name):
for student in student_score:
if student[1] == name:
try:
grade = student[2]
print("{}的成绩是：{}".format(name, grade))
return
except indexerror:
print('找不到该同学的成绩')
return
print("找不到该同学的信息")
return
student_score = [[1, "lily", 95], [2, "bob", 83], [3, "tom"], [4, "lis", 89]]
get_grade(student_score, "bob")
get_grade(student_score, "tom")
get_grade(student_score, "234")
总结
以上为个人经验，希望能给大家一个参考，也希望大家多多支持代码网。
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